An ideal reversible heat pump is taking heat from the outside air at -10.0°C and discharging it into the house at 18.0°C.What is the coefficient of performance of this heat pump?

Question

Quizplus · Accepted Answer

The coefficient of performance of a heat pump is given by the ratio of the heat output to the work input. For an ideal reversible heat pump, the coefficient of performance is given by:COP = Th / (Th - Tc)where Th is the temperature of the heat source (in Kelvin) and Tc is the temperature of the heat sink (in Kelvin).In this case, Th = 18.0°C + 273.15 = 291.15 K and Tc = -10.0°C + 273.15 = 263.15 K. Therefore, the coefficient of performance is:COP = 291.15 / (291.15 - 263.15) = 10.4

An Ideal Reversible Heat Pump Is Taking Heat from the Outside