The standard deviation of the sampling distribution of a sample proportion is $\sqrt { \frac { \pi ( 1 - \pi ) } { n } }$ where ? is the population proportion.

Question

Quizplus · Accepted Answer

This is true. The formula for the standard deviation of the sampling distribution of a sample proportion is:

σp = sqrt((π(1-π))/n)

where π is the population proportion and n is the sample size.

The Standard Deviation of the Sampling Distribution of a Sample π(1−π)n\sqrt { \frac { \pi ( 1 - \pi ) } { n } }nπ(1−π)​​

The Standard Deviation of the Sampling Distribution of a Sample $\sqrt { \frac { \pi ( 1 - \pi ) } { n } }$