When a metal surface is illuminated with light of wavelength 437 nm,the stopping potential for photoelectrons is 1.67 V.(c = 3.00 × 10⁸ m/s, , ,
1 eV = 1.60 × 10^-19 J,m_el = 9.11 × 10^-31 kg)
(a)What is the work function of the metal,in eV?
(b)What is the maximum speed of the ejected electrons?

Question

When a metal surface is illuminated with light of wavelength 437 nm,the stopping potential for photoelectrons is 1.67 V.(c = 3.00 × 10⁸ m/s,

When a metal surface is illuminated with light of wavelength 437 nm,the stopping potential for photoelectrons is 1.67 V.(c = 3.00 × 10<sup>8</sup> m/s, , , 1 eV = 1.60 × 10<sup>-19</sup> J,m<sub>el</sub> = 9.11 × 10<sup>-31</sup> kg) (a)What is the work function of the metal,in eV? (b)What is the maximum speed of the ejected electrons?

,

,
1 eV = 1.60 × 10^-19 J,m_el = 9.11 × 10^-31 kg)
(a)What is the work function of the metal,in eV?
(b)What is the maximum speed of the ejected electrons?

Quizplus · Accepted Answer

The Answer of When a metal surface is illuminated with light of wavelength 437 nm,the stopping potential for photoelectrons is 1.67 V.(c = 3.00 × 10⁸ m/s, , , 1 eV = 1.60 × 10^-19 J,m_el = 9.11 × 10^-31 kg) (a)What is the work function of the metal,in eV? (b)What is the maximum speed of the ejected electrons?

When a Metal Surface Is Illuminated with Light of Wavelength