An equation of the straight line passing through (1,-5)and (-2,4)is
A) x - 3y + 2 = 0.
B) x - 3y - 16 = 0.
C) x + 3y - 14 = 0.
D) 3x + y - 5 = 0.
E) 3x + y + 2 = 0.

Question

Quizplus · Accepted Answer

We can use the point-slope form of the equation of a line to find the equation passing through the given points.

First, we find the slope:

m = (y2 - y1)/(x2 - x1)

m = (4 - (-5))/(-2 - 1)

m = 9/-3

m = -3

Next, we use the point-slope form:

y - y1 = m(x - x1)

Using the point (1, -5):

y - (-5) = -3(x - 1)

y + 5 = -3x + 3

Subtract 5 from both sides:

y = -3x - 2

Multiplying both sides by 3, we get:

3y = -9x - 6

Adding 6 to both sides:

9x + 3y + 6 = 0

Dividing by 3, the final equation is:

3x + y + 2 = 0

Thus, the answer is E: 3x + y + 2 = 0.

An Equation of the Straight Line Passing Through (1,-5)and (-2,4)is