Coherent light of wavelength 540 nm passes through a pair of thin slits that are 3.4 × $10 ^{- 5}$ m apart.At what angle away from the centerline does the second bright fringe occur?

Question

Quizplus · Accepted Answer

The second bright fringe occurs at an angle given by:$$\theta = \sin^{-1}\left(\frac{m\lambda}{d}\right)$$where m is the order of the fringe (m = 2 for the second bright fringe), $\lambda$ is the wavelength of the light, and d is the distance between the slits. Plugging in the given values, we get:$$\theta = \sin^{-1}\left(\frac{2 \times 540 \times 10^{-9} \text{ m}}{3.4 \times 10^{-5} \text{ m}}\right) = 1.8^\circ$$

Coherent Light of Wavelength 540 Nm Passes Through a Pair 10−510 ^{- 5}10−5

Coherent Light of Wavelength 540 Nm Passes Through a Pair $10 ^{- 5}$