The equilibrium constant is given for two of the reactions below.Determine the value of the missing equilibrium constant. A(g) + B(g) ⇌ AB(g) Kc = 0.24
AB(g) + A(g) ⇌ A₂B(g) K_c = 3.8
2 A(g) + B(g) ⇌ A₂B(g) K_c = ?

Question

Quizplus · Accepted Answer

The third reaction is essentially the sum of the first two reactions. The equilibrium constant for a reaction that is the sum of two or more reactions is the product of the equilibrium constants of those reactions. Therefore, $K_c$ for the third reaction is $0.24 \times 3.8 = 0.912$, which rounds to 0.91.

The Equilibrium Constant Is Given for Two of the Reactions