If 0.1800 g of impure soda ash (Na₂CO₃)is titrated with 15.66 mL of 0.1082 M HCl,what is the percent purity of the soda ash? Na₂CO₃(aq)+ 2 HCl(aq)$\to$ 2 NaCl(aq)+ H₂O( )+ CO₂(g)

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The Answer of If 0.1800 g of impure soda ash (Na₂CO₃)is titrated with 15.66 mL of 0.1082 M HCl,what is the percent purity of the soda ash? Na₂CO₃(aq)+ 2 HCl(aq)$\to$ 2 NaCl(aq)+ H₂O( )+ CO₂(g)

If 01800 G of Impure Soda Ash (Na2CO3)is Titrated with 15

If 01800 G of Impure Soda Ash (Na₂CO₃)is Titrated with 15