There are 13 patients in Dr.Ziglar's waiting room.Dr.Ziglar can see 6 patients before lunch.In how many different orders can Dr.Ziglar see 6 of the patients before lunch?
A) 1716
B) 8,648,640
C) 78
D) 6
E) 1,235,520

Question

Quizplus · Accepted Answer

This is a permutations problem, where the order in which the patients are seen matters. The number of permutations of 6 patients from 13 is 13P6, which can be calculated as:
13P6 = 13!/7! = 13 x 12 x 11 x 10 x 9 x 8 = 1,235,520
Therefore, the answer is E.

There Are 13 Patients in Dr