What is the temperature (°C)of 2.48 moles of gas stored in a 30.0 L container at 1559 mm Hg?
(R= 0.0821 L atm/ mol K)

Name: What is the temperature (°C)of 2.48 moles of gas stored in a 30.0 L container at 1559 mm Hg? (R= 0.0821 L atm/ mol K)
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Question

Quizplus · Accepted Answer

Use the ideal gas law:

PV = nRT

P = 1559 mmHg = 1559/760 atm
n = 2.48 mol
V = 30.0 L
R = 0.0821 L atm / mol K

Rearranging the equation to solve for T:

T = PV / (nR)

T = (1559/760) atm * 30.0 L / (2.48 mol * 0.0821 L atm/mol K) = 29°C

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