What is the concentration of sodium chloride in the final solution if 25.34 mL of 0.113 M BaCl₂ completely reacts and the total volume of the reaction is 110.4 mL,given the reaction:
BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

Question

Quizplus · Accepted Answer

First, we need to determine the number of moles of BaCl2 that reacted:
0.113 mol/L x 0.02534 L = 0.002864 mol BaCl2

Since the stoichiometry of the reaction is 1:2 for BaCl2:NaCl, we know that twice the number of moles of NaCl were produced:
2 x 0.002864 mol = 0.005728 mol NaCl

Next, we need to determine the final concentration of NaCl in the solution:
0.005728 mol / 0.1104 L = 0.0519 mol/L or 0.0519 M

Therefore, the correct choice is C, with a final concentration of 0.0519 M.

What Is the Concentration of Sodium Chloride in the Final