If a mixture of gases contained 78% nitrogen at a pressure of
And 22% carbon dioxide at
,what is the total pressure of the system?

Question

If a mixture of gases contained 78% nitrogen at a pressure of 
And 22% carbon dioxide at 
,what is the total pressure of the system?

Quizplus · Accepted Answer

To find the total pressure of a mixture of gases, we use Dalton's Law of Partial Pressure, which states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas. The partial pressure of each gas is equal to the mole fraction of that gas (the fraction of moles of that gas in the mixture) times the total pressure of the mixture.

In this problem, we are given the mole fraction of nitrogen and carbon dioxide in the mixture, which are 0.78 and 0.22, respectively. We are also given the partial pressure of nitrogen and carbon dioxide, which are 11ea8a6b_bbbc_1247_9ee3_0dfe6dce4a34_TB6109_11
and 11ea8a6b_bbbc_1248_9ee3_7989a43adaa4_TB6109_11
, respectively.

Using Dalton's Law of Partial Pressure, we can calculate the total pressure of the system as:

Total pressure = (partial pressure of nitrogen) + (partial pressure of carbon dioxide)
Total pressure = (0.78)(11ea8a6b_bbbc_1247_9ee3_0dfe6dce4a34_TB6109_11) + (0.22)(11ea8a6b_bbbc_1248_9ee3_7989a43adaa4_TB6109_11)
Total pressure ≈ 1.75 atm

Therefore, the answer is choice D) 1.75 atm.

If a Mixture of Gases Contained 78% Nitrogen at a Pressure