For the reaction 2 A ⇌ B,the equilibrium concentrations are as follows: [A] = 0.056 M and [B] = 0.12 M.Calculate the equilibrium constant (
)for the reaction.

Question

For the reaction 2 A ⇌ B,the equilibrium concentrations are as follows: [A] = 0.056 M and [B] = 0.12 M.Calculate the equilibrium constant ( 
)for the reaction.

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is:
Kc = [B] / [A]^2
Substituting the given equilibrium concentrations:
Kc = (0.12) / (0.056)^2
Kc = 38 (rounded to the nearest whole number)
Therefore, the best choice is D.

For the Reaction 2 a ⇌ B,the Equilibrium Concentrations Are