If the energy of n = 3 is -1.51 eV and that of n = 4 is -0.85 eV in a hydrogen atom, a transition from n = 3 to n = 4 will _______________ a photon with an energy of approximately ______________.

Question

Quizplus · Accepted Answer

A transition from n = 3 to n = 4 in a hydrogen atom involves moving to a higher energy level, which requires absorbing energy. The energy difference is 0.85 eV - (-1.51 eV) = 0.661 eV, so a photon with this energy is absorbed.

If the Energy of N = 3 Is -1