Lori built a dog lot for her dog, Chollie, by fencing in a rectangular area of her yard. If Chollie's lot required 52 feet of fence and the length is 2 feet longer than the width, then what are the length and width of Chollie's dog lot?
A) 6 feet long and 20 feet wide
B) 18 feet long and 8 feet wide
C) 10 feet long and 16 feet wide
D) 14 feet long and 12 feet wide

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by the formula $P = 2l + 2w$, where $l$ is the length and $w$ is the width. Given that the length is 2 feet longer than the width ($l = w + 2$) and the total perimeter is 52 feet, we can set up the equation $52 = 2(w + 2) + 2w$. Simplifying this equation gives us $52 = 4w + 4$, and solving for $w$ gives us $w = 12$. Substituting back to find $l$, we get $l = 12 + 2 = 14$. Therefore, the dimensions are 14 feet by 12 feet.

Lori Built a Dog Lot for Her Dog, Chollie, by Fencing