Light from a He-Ne laser of wavelength 633 nm passes through a circular aperture.It is observed on a screen 4.0 m behind the aperture.The width of the central maximum is 5.4 cm.What is the diameter of the hole?

Question

Quizplus · Accepted Answer

The width of the central maximum in a diffraction pattern is given by the formula: width = 2 * (wavelength * distance) / diameter. Rearranging for diameter and substituting the given values, we find the diameter to be approximately 110 μm.

Light from a He-Ne Laser of Wavelength 633 Nm Passes