Instruction 15-3
A computer used by a 24-hour banking service is supposed to randomly assign each transaction to one of five memory locations.A check at the end of a day's transactions gave the counts shown in the table to each of the five memory locations,along with the number of reported errors.
$$\begin{array} { | l | l | l | l | l | l | }
\hline \text { Memory Location } & 1 & 2 & 3 & 4 & 5 \
\hline \text { Number of Transactions } & 82 & 100 & 74 & 92 & 102 \
\hline \text { Number of Reported Errors } & 11 & 12 & 6 & 9 & 10 \
\hline
\end{array}$$ The bank manager wanted to test whether the proportion of errors in transactions assigned to each of the five memory locations differ.
-Referring to Instruction 15-3,the degrees of freedom of the test statistic is
A)4.
B)8.
C)448.
D)10.

Question

Instruction 15-3
A computer used by a 24-hour banking service is supposed to randomly assign each transaction to one of five memory locations.A check at the end of a day's transactions gave the counts shown in the table to each of the five memory locations,along with the number of reported errors.
 $$\begin{array} { | l | l | l | l | l | l | } 
\hline \text { Memory Location } & 1 & 2 & 3 & 4 & 5 \
\hline \text { Number of Transactions } & 82 & 100 & 74 & 92 & 102 \
\hline \text { Number of Reported Errors } & 11 & 12 & 6 & 9 & 10 \
\hline
\end{array}$$ The bank manager wanted to test whether the proportion of errors in transactions assigned to each of the five memory locations differ.
-Referring to Instruction 15-3,the degrees of freedom of the test statistic is
A)4.
B)8.
C)448.
D)10.

Quizplus · Accepted Answer

The degrees of freedom for a chi-square test for homogeneity or independence is calculated as (number of categories - 1). Here, there are 5 memory locations, so the degrees of freedom is 5 - 1 = 4.

Instruction 15-3 a Computer Used by a 24-Hour Banking Service

Instruction 15-3
a Computer Used by a 24-Hour Banking Service