Determine the value of sin t when t = $\frac { 11 \pi } { 2 }$ .
A) 1
B) $\frac { 1 } { 2 }$
C) -1
D) 0
E) none of these

Name: Determine the value of sin t when t = $\frac { 11 \pi } { 2 }$ . A) 1 B) $\frac { 1 } { 2 }$ C) -1 D) 0 E) none of these
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Question

Quizplus · Accepted Answer

The sine function has a period of 2π, which means that it repeats itself every 2π units. Therefore, sin(11π/2) = sin(11π/2 - 2π) = sin(-π/2) = -1.

Determine the Value of Sin T When T = 11π2\frac { 11 \pi } { 2 }211π​

Determine the Value of Sin T When T = $\frac { 11 \pi } { 2 }$