In a large city, the amount of sulfur dioxide pollutant released into the atmosphere due to the burning of coal and oil for heating purposes is given approximately by $P ( t ) = 3 + \cos \frac { \pi t } { 26 }$ for $0 \leq \mathrm { t } \leq 104$ where P(t) is the amount of sulfur dioxide in tons released during the nth week after January 1. How many tons (to the nearest ton) of pollutants were emitted into the atmosphere from t = 0 to t = 65?
A) 221 tons
B) 4 tons
C) 196 tons
D) 203 tons

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The Answer of In a large city, the amount of sulfur dioxide pollutant released into the atmosphere due to the burning of coal and oil for heating purposes is given approximately by $P ( t ) = 3 + \cos \frac { \pi t } { 26 }$ for $0 \leq \mathrm { t } \leq 104$ where P(t) is the amount of sulfur dioxide in tons released during the nth week after January 1. How many tons (to the nearest ton) of pollutants were emitted into the atmosphere from t = 0 to t = 65?
A) 221 tons
B) 4 tons
C) 196 tons
D) 203 tons

In a Large City, the Amount of Sulfur Dioxide Pollutant P(t)=3+cos⁡πt26P ( t ) = 3 + \cos \frac { \pi t } { 26 }P(t)=3+cos26πt​

In a Large City, the Amount of Sulfur Dioxide Pollutant $P ( t ) = 3 + \cos \frac { \pi t } { 26 }$