Solve for x.
-3 + ln x = 0
A) x = ln(-3)
B) x = $\frac { 1 } { \mathrm { e } ^ { 3 } }$
C) x = ln $\left( \frac { 1 } { 3 } \right)$
D) x = - $\mathrm { e } ^ { 3 }$
E) none of these

Question

Solve for x. 
-3 + ln x = 0
A) x = ln(-3)
B) x = $\frac { 1 } { \mathrm { e } ^ { 3 } }$
C) x = ln $\left( \frac { 1 } { 3 } \right)$
D) x = - $\mathrm { e } ^ { 3 }$
E) none of these

Quizplus · Accepted Answer

To solve for $x$, we first isolate $ln(x)$ by subtracting 3 from both sides, giving $ln(x) = -3$. To remove the natural logarithm, we exponentiate both sides with base $e$, resulting in $x = e^{-3}$, which simplifies to $\frac{1}{e^3}$.

Solve for X 1e3\frac { 1 } { \mathrm { e } ^ { 3 } }e31​

Solve for X $\frac { 1 } { \mathrm { e } ^ { 3 } }$