Suppose X is a normal random variable with density function $f ( x ) = \frac { 1 } { \sqrt { 2 \pi } } \mathrm { e } ^ { ( - 1 / 2 ) ( x + 4 ) ^ { 2 } }$ . Find the expected value and standard deviation of X.
A) μ = -4, σ = 1
B) μ = 1, σ = 4
C) μ = 1, σ = 16
D) μ = 4, σ = 1
E) μ = -4, σ = 16

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The Answer of Suppose X is a normal random variable with density function $f ( x ) = \frac { 1 } { \sqrt { 2 \pi } } \mathrm { e } ^ { ( - 1 / 2 ) ( x + 4 ) ^ { 2 } }$ . Find the expected value and standard deviation of X.
A) μ = -4, σ = 1
B) μ = 1, σ = 4
C) μ = 1, σ = 16
D) μ = 4, σ = 1
E) μ = -4, σ = 16

Suppose X Is a Normal Random Variable with Density Function f(x)=12πe(−1/2)(x+4)2f ( x ) = \frac { 1 } { \sqrt { 2 \pi } } \mathrm { e } ^ { ( - 1 / 2 ) ( x + 4 ) ^ { 2 } }f(x)=2π​1​e(−1/2)(x+4)2

Suppose X Is a Normal Random Variable with Density Function $f ( x ) = \frac { 1 } { \sqrt { 2 \pi } } \mathrm { e } ^ { ( - 1 / 2 ) ( x + 4 ) ^ { 2 } }$