Suppose a fair die is rolled 13 times. What is the probability that 1 "aces" (1's) will occur? Round your answer to six digital places.
A)Pr(1 Aces) = 0.033399
B)Pr(1 Aces) = 0.001587
C)Pr(1 Aces) = 0.000016
D)Pr(1 Aces) = 0.000000
E)Pr(1 Aces) = 0.243006

Question

Suppose a fair die is rolled 13 times. What is the probability that 1 "aces" (1's) will occur? Round your answer to six digital places. ​
A)Pr(1 Aces) = 0.033399
B)Pr(1 Aces) = 0.001587
C)Pr(1 Aces) = 0.000016
D)Pr(1 Aces) = 0.000000
E)Pr(1 Aces) = 0.243006

Quizplus · Accepted Answer

The probability of getting exactly one ace in 13 rolls of a fair die can be calculated using the binomial probability formula: $P(X=k) = \binom{n}{k}p^k(1-p)^{n-k}$, where $n=13$, $k=1$, and $p=\frac{1}{6}$ (the probability of rolling an ace). Plugging these values into the formula gives a probability of approximately 0.243006.

Suppose a Fair Die Is Rolled 13 Times