Suppose that the profit from the sale of Kandy and Kreams is given by dollars, where x is the number of pounds of Kandy and y is the number of pounds of Kreams. How many pounds of Kandy and Kreams must be sold to maximize profit? What is the maximum profit? Round your pounds answers to the nearest whole number. Round your max profit answer to the nearest cent.
A) 40 pounds of Kandy, 200 pounds of Kreams, max profit of $661.00
B) 6 pounds of Kandy, 15 pounds of Kreams, max profit of $477.45
C) 12 pounds of Kandy, 30 pounds of Kreams, max profit of $865.80
D) 20 pounds of Kandy, 100 pounds of Kreams, max profit of $1,620.00
E) 60 pounds of Kandy, 300 pounds of Kreams, max profit of $315.34

Question

Suppose that the profit from the sale of Kandy and Kreams is given by  dollars, where x is the number of pounds of Kandy and y is the number of pounds of Kreams. How many pounds of Kandy and Kreams must be sold to maximize profit? What is the maximum profit? Round your pounds answers to the nearest whole number. Round your max profit answer to the nearest cent. ​
A) 40 pounds of Kandy, 200 pounds of Kreams, max profit of $661.00 
B) 6 pounds of Kandy, 15 pounds of Kreams, max profit of $477.45 
C) 12 pounds of Kandy, 30 pounds of Kreams, max profit of $865.80 
D) 20 pounds of Kandy, 100 pounds of Kreams, max profit of $1,620.00 
E) 60 pounds of Kandy, 300 pounds of Kreams, max profit of $315.34

Quizplus · Accepted Answer

To maximize profit, we need to find the critical point of the given function. Taking partial derivatives and setting them equal to zero, we get:
11 - 0.02x - 0.05y = 0
and
11 - 0.05x - 0.02y = 0
Solving these equations simultaneously, we get x = 20 and y = 100. Therefore, 20 pounds of Kandy and 100 pounds of Kreams must be sold to maximize profit. Substituting these values back into the given function, we get maximum profit of $1,620.00.

Suppose That the Profit from the Sale of Kandy and Kreams