A solid steel sphere with a radius of 2.0 m falls off a ship and sinks to a depth where the pressure is 15 MN/m². The bulk modulus for this steel is 1.6 × 10¹¹ N/m². What is the change in the radius of the sphere? A) -0.021 mm B) -4.2 mm C) -0.42 mm D) -0.19 mm E) -0.062 mm

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Quizplus · Accepted Answer

The change in volume due to pressure can be calculated using the formula for bulk modulus: ΔV/V = -ΔP/B. For a sphere, the change in radius can be derived from the change in volume. Using the given values, the change in radius is approximately -0.062 mm.

A Solid Steel Sphere with a Radius of 2