3.00 moles of an ideal gas at a pressure of 250 kPa are held in a container of volume of 25.0 L. The ideal gas constant is R = 8.314 J/mol•K = 0.0821 L ∙ atm/mol ∙ K, and 1 atm = 1.01 x 10⁵ Pa. The temperature of this gas is closest to

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First, convert pressure from kPa to atm: 250 kPa = 250,000 Pa = 250,000 / 101,000 atm ≈ 2.475 atm. Use the ideal gas law: PV = nRT. Solve for T: T = PV / (nR) = (2.475 atm * 25.0 L) / (3.00 mol * 0.0821 L∙atm/mol∙K) ≈ 251 K. Convert to Celsius: 251 K - 273.15 ≈ -22°C.

300 Moles of an Ideal Gas at a Pressure of 250