What is the average kinetic energy of an ideal gas molecule at 569°C? (The Boltzmann constant is 1.38 × 10^-23 J/K.) A) 1.74 × 10^-20 J B) 5.81 × 10^-21 J C) 1.18 × 10^-17 J D) 3.93 × 10^-19 J

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Quizplus · Accepted Answer

The average kinetic energy of an ideal gas molecule is given by (3/2)kT, where k is the Boltzmann constant and T is the temperature in Kelvin. Converting 569°C to Kelvin gives 842 K. Plugging in the values: (3/2) * 1.38 × 10^-23 J/K * 842 K = 1.74 × 10^-20 J.

What Is the Average Kinetic Energy of an Ideal Gas