Suppose two AaBbCc individuals are mated. Assuming that the genes are NOT linked, what fraction of the offspring are expected to be homozygous recessive for the three traits?
A) 1/4
B) 1/8
C) 1/16
D) 1/64
E) 1/256

Question

Quizplus · Accepted Answer

For each gene (A, B, C), the chance of an offspring being homozygous recessive (aa, bb, cc) is 1/4, since each parent can contribute a recessive allele with a probability of 1/2. Since the genes are not linked and assort independently, the probability of an offspring being homozygous recessive for all three traits is (1/4) * (1/4) * (1/4) = 1/64.

Suppose Two AaBbCc Individuals Are Mated