A gasoline engine absorbs 2 500 J of heat at 250 $\degree$C and expels 2 000 J at a temperature of 50 $\degree$C.The magnitude of the change in entropy (in J/K)for the system is

Question

Quizplus · Accepted Answer

The change in entropy of the system can be calculated using the formula:
ΔS = Q/T
where ΔS is the change in entropy, Q is the heat absorbed or released, and T is the temperature in Kelvin.

Converting the temperatures to Kelvin:
250°F = (250 + 460)°R = 710°K
50°F = (50 + 460)°R = 510°K

Substituting the values:
ΔS = (2500 J - 2000 J) / 710 K
ΔS = 500 J / 710 K
ΔS = 0.704 J/K

Rounding to one significant figure:
ΔS = 1 J/K

The closest answer choice is C) 1.4, with a difference of 0.4, which can be attributed to rounding errors.

A Gasoline Engine Absorbs 2 500 J of Heat at 250