A 0.28-kg stone you throw rises 34.3 m in the air.The magnitude of the impulse the stone received from your hand while being thrown is
A)0.27 N's
B)2.7 N's
C)7.3 N's
D)9.6 N's
E)34.3 N's

Question

Quizplus · Accepted Answer

Impulse is equal to the change in momentum. The stone's final velocity at the peak is 0 m/s, and using the equation $v^2 = u^2 + 2as$, we find the initial velocity $u$. Then, impulse $J = m \cdot \Delta v$. Solving gives approximately 7.3 N's.

A 028-Kg Stone You Throw Rises 34