With a 90 percent confidence interval for the difference between the proportions of failures in factory 1 and factory 2 where ₁ = .05, ₂ = .04,n₁= 500,n₂ = 2000 of (-.0076 .0276)can we reject the null hypothesis at $\alpha$ = .10?

Question

Quizplus · Accepted Answer

The confidence interval includes zero, which means that the difference between the proportions of failures in factory 1 and factory 2 is not statistically significant. Therefore, we cannot reject the null hypothesis at F1F1F1S1αF1F1F10=.10.

With a 90 Percent Confidence Interval for the Difference Between α\alphaα

With a 90 Percent Confidence Interval for the Difference Between $\alpha$