To investigate the rate at which employees with cancer are fired or laid off,a telephone survey was taken of 100 cancer survivors who worked while undergoing treatment.Seven (7)were either fired or laid off due to their illness.Construct a 90% confidence interval for the true percentage of all cancer patients who are fired or laid off due to their illness.
A)[0.0000 0.2034]
B)[0.0371 0.1029]
C)[0.0039 0.1361]
D)[0.0278 0.1122]
E)[0.0078 0.1400]

Question

Quizplus · Accepted Answer

The sample proportion is 7/100 = 0.07. Using the formula for a confidence interval for a proportion, the 90% confidence interval is calculated as 0.07 ± 1.645 * sqrt((0.07*(1-0.07))/100), which results in the interval [0.0278, 0.1122].

To Investigate the Rate at Which Employees with Cancer Are