During the past six months,73.2% of US households purchased sugar.Assume that these expenditures are approximately normally distributed with a mean of $8.22 and a standard deviation of $1.10. Find the probability that a household spent more than $10.00
A).7320
B).9474
C).0526
D).2680

Question

Quizplus · Accepted Answer

We need to find the probability that a household spent more than $10.00.

Using the z-score formula:

z = (x - μ) / σ

where x is the value we are interested in (in this case, x = $10.00), μ is the mean ($8.22), and σ is the standard deviation ($1.10).

z = (10.00 - 8.22) / 1.10 = 1.62

From the z-tables, we can find that the probability of a standard normal distribution being greater than 1.62 is 0.0526 (or approximately 5.26%).

Therefore, the probability that a household spent more than $10.00 is 0.0526 or 5.26%.

Hence, the answer is Choice C.

During the Past Six Months,73