The J.O.Supplies Company buys calculators from a Korean supplier.The probability of a defective calculator is 10%. If 3 calculators are selected at random,what is the probability that one of the calculators will be defective?
A).0702
B).0010
C).2430
D).7290

Question

Quizplus · Accepted Answer

To find the probability that one of the calculators will be defective, we can use the binomial distribution formula:

P(X = 1) = (nC1) * p^1 * q^(n-1)

where n = 3 (number of calculators selected), p = 0.1 (probability of a defective calculator), q = 0.9 (probability of a non-defective calculator), and nC1 is the number of ways to select 1 defective calculator out of 3.

nC1 = 3C1 = 3

Plugging these values into the formula, we get:

P(X = 1) = 3 * 0.1^1 * 0.9^2 = 0.243

Therefore, the probability that one of the calculators will be defective is 0.243, which is closest to option C (0.2430).

The JOSupplies Company Buys Calculators from a Korean Supplier