The pupil area of the human eye is ~ 1 $\times$ 10^-5 m².The minimum light intensity that the eye is sensitive to is ~ 1 $\times$ 10^-10 Wm^-2.How many photons per second of wavelength 550 nm does this correspond to? A)~300 s^-1 B)~30000 s^-1 C)~3000 s^-1 D)~3 $\times$ 10^-2 s^-1 E)~3 $\times$ 10¹² s^-1

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The Answer of The pupil area of the human eye is ~ 1 $\times$ 10^-5 m².The minimum light intensity that the eye is sensitive to is ~ 1 $\times$ 10^-10 Wm^-2.How many photons per second of wavelength 550 nm does this correspond to? A)~300 s^-1 B)~30000 s^-1 C)~3000 s^-1 D)~3 $\times$ 10^-2 s^-1 E)~3 $\times$ 10¹² s^-1

The Pupil Area of the Human Eye Is ~ 1 ×\times×

The Pupil Area of the Human Eye Is ~ 1 $\times$