The resistivity of iron at 20ºC is 10 $\times$ 10^-8 $\Omega$ · m and the number of electrons per cubic centimeter is 17.0 $\times$ 10²².If you take the average speed of the electrons to be equal to their root-mean-square speed (at T = 300 K)of 1.17 $\times$ 10⁵ m/s,it follows that their mean free path,$\lambda$ ,must be A)0.245 nm B)0.317 nm C)0.428 nm D)0.556 nm E)None of these is correct.

Question

Quizplus · Accepted Answer

The mean free path can be calculated using the formula λ = (m * v) / (n * e² * ρ), where m is the electron mass, v is the speed, n is the number density, e is the electron charge, and ρ is the resistivity. Substituting the given values, the mean free path is approximately 0.245 nm.

The Resistivity of Iron at 20ºC Is 10 ×\times× 10-8 Ω\OmegaΩ · M and the Number of Electrons Per Cubic Centimeter

The Resistivity of Iron at 20ºC Is 10 $\times$ 10^-8 $\Omega$ · M and the Number of Electrons Per Cubic Centimeter