A broad spectrum of light ($\lambda$ = 550 nm) illuminates normally a thin wedge of glass (n = 1.50). If the thick edge of the glass is 0.02 mm, the number of dark fringes observed is
A) 109
B) 99
C) 73
D) 55
E) 33

Question

A broad spectrum of light ($\lambda$ = 550 nm) illuminates normally a thin wedge of glass (n = 1.50). If the thick edge of the glass is 0.02 mm, the number of dark fringes observed is
A) 109 
B) 99 
C) 73 
D) 55 
E) 33

Quizplus · Accepted Answer

The Answer of  A broad spectrum of light ($\lambda$ = 550 nm) illuminates normally a thin wedge of glass (n = 1.50). If the thick edge of the glass is 0.02 mm, the number of dark fringes observed is
A) 109 
B) 99 
C) 73 
D) 55 
E) 33

A Broad Spectrum of Light λ\lambdaλ = 550 Nm) Illuminates Normally a Thin Wedge of Glass

A Broad Spectrum of Light $\lambda$ = 550 Nm) Illuminates Normally a Thin Wedge of Glass