Use polar coordinates to evaluate. $\int _ { - 4 } ^ { 4 } \int _ { 0 } ^ { \sqrt { 16 - x ^ { 2 } } } \sin \left( x ^ { 2 } + y ^ { 2 } \right) d x d y$

Name: Use polar coordinates to evaluate. $\int _ { - 4 } ^ { 4 } \int _ { 0 } ^ { \sqrt { 16 - x ^ { 2 } } } \sin \left( x ^ { 2 } + y ^ { 2 } \right) d x d y$
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The Answer of Use polar coordinates to evaluate. $\int _ { - 4 } ^ { 4 } \int _ { 0 } ^ { \sqrt { 16 - x ^ { 2 } } } \sin \left( x ^ { 2 } + y ^ { 2 } \right) d x d y$

Use Polar Coordinates to Evaluate ∫−44∫016−x2sin⁡(x2+y2)dxdy\int _ { - 4 } ^ { 4 } \int _ { 0 } ^ { \sqrt { 16 - x ^ { 2 } } } \sin \left( x ^ { 2 } + y ^ { 2 } \right) d x d y∫−44​∫016−x2​​sin(x2+y2)dxdy

Use Polar Coordinates to Evaluate $\int _ { - 4 } ^ { 4 } \int _ { 0 } ^ { \sqrt { 16 - x ^ { 2 } } } \sin \left( x ^ { 2 } + y ^ { 2 } \right) d x d y$