A mortar shell is fired with a muzzle speed of 325 ft/sec. Find the angle of elevation of the mortar if the shell strikes a target located 1500 ft away. Round your answer to 2 decimal places.
A) $12.22 ^ { \circ }$
B) $0.64 ^ { \circ }$
C) $13.51 ^ { \circ }$
D) $0.24 ^ { \circ }$

Question

Quizplus · Accepted Answer

We can use the range formula $R=\frac{V_i^2}{g}\sin 2	heta$, where $R$ is the range, $V_i$ is the initial velocity, $g$ is acceleration due to gravity, and $	heta$ is the angle of elevation. 
Plugging in the given values, we get $1500=\frac{325^2}{32.2}\sin 2	heta$. 
Simplifying, we get $\sin 2	heta = \frac{1500\cdot 32.2}{325^2}$. 
Using the inverse sine function, we get $	heta \approx 13.51^{\circ}$. 
Therefore, the answer is C.

A Mortar Shell Is Fired with a Muzzle Speed of 325