Find the radius of convergence and the interval of convergence of the power series. $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } ( x - 6 ) ^ { n } } { n \cdot 5 ^ { n } }$
A) $R = 6 , I = ( - 1,11 ]$
B) $R = 5 , I = ( 1,11 ]$
C) $R = \frac { 1 } { 5 } , I = \left[ - \frac { 1 } { 5 } , \frac { 1 } { 5 } \right)$
D) $R = 5 , I = [ - 5,5 )$

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The Answer of Find the radius of convergence and the interval of convergence of the power series. $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } ( x - 6 ) ^ { n } } { n \cdot 5 ^ { n } }$
A) $R = 6 , I = ( - 1,11 ]$
B) $R = 5 , I = ( 1,11 ]$
C) $R = \frac { 1 } { 5 } , I = \left[ - \frac { 1 } { 5 } , \frac { 1 } { 5 } \right)$
D) $R = 5 , I = [ - 5,5 )$

Find the Radius of Convergence and the Interval of Convergence ∑n=1∞(−1)n−1(x−6)nn⋅5n\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } ( x - 6 ) ^ { n } } { n \cdot 5 ^ { n } }∑n=1∞​n⋅5n(−1)n−1(x−6)n​

Find the Radius of Convergence and the Interval of Convergence $\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n - 1 } ( x - 6 ) ^ { n } } { n \cdot 5 ^ { n } }$