The base of S is a circular region with boundary curve $6 x^{2}+6 y^{2}=24$ Cross-sections perpendicular to the x axis are isosceles right triangles with hypotenuse in the base.
Find the volume of S.

Question

Quizplus · Accepted Answer

The Answer of The base of S is a circular region with boundary curve $6 x^{2}+6 y^{2}=24$ Cross-sections perpendicular to the x axis are isosceles right triangles with hypotenuse in the base.
Find the volume of S.

The Base of S Is a Circular Region with Boundary 6x2+6y2=246 x^{2}+6 y^{2}=246x2+6y2=24

The Base of S Is a Circular Region with Boundary $6 x^{2}+6 y^{2}=24$