Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. $h(x)=\int_{1}^{\sqrt{x}} \frac{2 z^{2}}{z^{4}+1} d z$

Name: Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. $h(x)=\int_{1}^{\sqrt{x}} \frac{2 z^{2}}{z^{4}+1} d z$
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The Answer of Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. $h(x)=\int_{1}^{\sqrt{x}} \frac{2 z^{2}}{z^{4}+1} d z$

Use Part 1 of the Fundamental Theorem of Calculus to Find