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Question 5
Find the inverse function of f(x) =x+12x+1f(x) =\frac{x+1}{2 x+1}f(x) =2x+1x+1 .
A) f−1(x) =−x−12x−1f^{-1}(x) =-\frac{x-1}{2 x-1}f−1(x) =−2x−1x−1 B) f−1(x) =x2x−1f^{-1}(x) =\frac{x}{2 x-1}f−1(x) =2x−1x C) f−1(x) =(x+1) (2x+1) f^{-1}(x) =(x+1) (2 x+1) f−1(x) =(x+1) (2x+1) D) f−1(x) =−2x+1x−1f^{-1}(x) =-\frac{2 x+1}{x-1}f−1(x) =−x−12x+1 E) f−1(x) =−(x+1) (2x+1) f^{-1}(x) =-(x+1) (2 x+1) f−1(x) =−(x+1) (2x+1)
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Q1: If Q2: Find the exact value of theQ3: Find the exact value of theQ4: Simplify the expression. Q6: Find Q7: Determine whether the function is one-to-one.Q8: Find the exact value of theQ9: Use the laws of logarithms toQ10: Solve the equation. Q11: Simplify the expression.
Q2: Find the exact value of the
Q3: Find the exact value of the
Q4: Simplify the expression.
Q6: Find
Q7: Determine whether the function is one-to-one.
Q8: Find the exact value of the
Q9: Use the laws of logarithms to
Q10: Solve the equation.
Q11: Simplify the expression.
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