Find the domain of the function $f(x)=\frac{x}{-2 \sin x-3}$
A) $[2,3]$
B) $[-3,-2]$
C) $\left[-\frac{3}{2}, \infty\right)$
D) $(-\infty, \infty)$

Name: Find the domain of the function $f(x)=\frac{x}{-2 \sin x-3}$ A) $[2,3]$ B) $[-3,-2]$ C) $\left[-\frac{3}{2}, \infty\right)$ D) $(-\infty, \infty)$
Brand: Quizplus
Rating: 4.7 (29 reviews)

Question

Quizplus · Accepted Answer

The domain of the function is all real numbers except for the values of x that make the denominator zero. Since $-2 \sin x-3$ is never zero, the domain of the function is $(-\infty, \infty)$.

Find the Domain of the Function f(x)=x−2sin⁡x−3f(x)=\frac{x}{-2 \sin x-3}f(x)=−2sinx−3x​ A) [2,3][2,3][2,3] B) [−3,−2][-3,-2][−3,−2]

Find the Domain of the Function $f(x)=\frac{x}{-2 \sin x-3}$ A) $[2,3]$ B) $[-3,-2]$