Evaluate $\lim _ { x \rightarrow 0 } \frac { 2 x ^ { 2 } + x - 9 } { x - 2 }$ , and justify each step by indicating the appropriate Limit Law(s).

Name: Evaluate $\lim _ { x \rightarrow 0 } \frac { 2 x ^ { 2 } + x - 9 } { x - 2 }$ , and justify each step by indicating the appropriate Limit Law(s).
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\lim _ { x \rightarrow 0 } \frac { 2 x ^ { 2 } + x - 9 } { x - 2 } = \frac { \lim _ { x \rightarrow 0 } \left( 2 x ^ { 2 } + x - 9 \right) } { \lim _ { x \rightarrow 0 } ( x - 2 ) } = \frac { \lim _ { x \rightarrow 0 } \left( 2 x ^ { 2 } + x - 9 \right) } { \lim _ { x \rightarrow 0 } ( x - 2 ) } = \frac { 2 \lim _ { x \rightarrow 0 } x ^ { 2 } + \lim _ { x \rightarrow 0 } x - \lim _ { x \rightarrow 0 } 9 } { \lim _ { x \rightarrow 0 } x - \lim _ { x \rightarrow 0 } 2 } = \frac { 9 } { 2 }

Evaluate lim⁡x→02x2+x−9x−2\lim _ { x \rightarrow 0 } \frac { 2 x ^ { 2 } + x - 9 } { x - 2 }limx→0​x−22x2+x−9​

Evaluate $\lim _ { x \rightarrow 0 } \frac { 2 x ^ { 2 } + x - 9 } { x - 2 }$