Solve the system of equations $\left\{ \begin{aligned}
3 x + 2 y & = 8 \
x - 2 y & = 0
\end{aligned} \right.$ by converting to a matrix equation and using its inverse coefficient matrix $\left[ \begin{array} { c c }
\frac { 1 } { 4 } & \frac { 1 } { 4 } \
\frac { 1 } { 8 } & - \frac { 3 } { 8 }
\end{array} \right]$ .

Question

Solve the system of equations $\left\{ \begin{aligned}
3 x + 2 y & = 8 \
x - 2 y & = 0
\end{aligned} \right.$ by converting to a matrix equation and using its inverse coefficient matrix $\left[ \begin{array} { c c } 
\frac { 1 } { 4 } & \frac { 1 } { 4 } \
\frac { 1 } { 8 } & - \frac { 3 } { 8 }
\end{array} \right]$ .

Quizplus · Accepted Answer

The Answer of Solve the system of equations $\left\{ \begin{aligned}
3 x + 2 y & = 8 \
x - 2 y & = 0
\end{aligned} \right.$ by converting to a matrix equation and using its inverse coefficient matrix $\left[ \begin{array} { c c } 
\frac { 1 } { 4 } & \frac { 1 } { 4 } \
\frac { 1 } { 8 } & - \frac { 3 } { 8 }
\end{array} \right]$ .

Solve the System of Equations {3x+2y=8x−2y=0\left\{ \begin{aligned}3 x + 2 y & = 8 \\x - 2 y & = 0\end{aligned} \right.{3x+2yx−2y​=8=0​

Solve the System of Equations $\left\{ \begin{aligned}3 x + 2 y & = 8 \\x - 2 y & = 0\end{aligned} \right.$