Find $A \cup B$ if $A = \{ x \mid x \pi \}$ and $B = \{ x \mid - 1

Question

Find $A \cup B$ if $A = \{ x \mid x > \pi \}$ and $B = \{ x \mid - 1 < x < \pi \}$ . A) $\varnothing$ B) $\{ x \mid x > - 1 \text { and } x \neq \pi \}$ C) $\{ x \mid - 1 < x < \pi \}$ D) $\{ x \mid - \pi < x \leq 1 \}$ E) $\{ x \mid x > - \pi \}$

Quizplus · Accepted Answer

The union of sets A and B, $A \cup B$, includes all elements that are in A, in B, or in both. Set A includes all numbers greater than $\pi$, and set B includes all numbers strictly between -1 and $\pi$. Therefore, their union covers all numbers greater than -1 but excludes $\pi$, as $\pi$ is not strictly greater than itself.

Find A∪BA \cup BA∪B If A={x∣x>π}A = \{ x \mid x > \pi \}A={x∣x>π}

Find $A \cup B$ If $A = \{ x \mid x > \pi \}$