During the lunar mission of Apollo 11,Armstrong and Aldrin descended to the moon's surface in the lunar module while Collins remained in orbit in the command module.If the command module's period was 2 hours and 20 minutes,how high above the moon's surface did it orbit? (m_moon = 7.35 $\times$ 10²² kg,R_moon = 1.74 $\times$ 10⁶ m,and G = 6.67 $\times$10^-11 N · m²/kg².) A)3.22 $\times$ 10⁵ m B)1.04 $\times$ 10¹¹ m C)5.67 $\times$ 10² m D)2.53 $\times$ 10³ m E)Not enough information is given to answer this question.

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Quizplus · Accepted Answer

The orbital height can be calculated using the formula for the orbital period of a satellite: $T = 2\pi\sqrt{\frac{r^3}{GM}}$, where $T$ is the orbital period, $r$ is the distance from the center of the moon to the satellite (which is the sum of the moon's radius and the altitude of the orbit), $G$ is the gravitational constant, and $M$ is the mass of the moon. Given the period, the mass of the moon, the radius of the moon, and $G$, we can solve for $r$ and then subtract the moon's radius to find the altitude of the orbit.

During the Lunar Mission of Apollo 11,Armstrong and Aldrin Descended ×\times×

During the Lunar Mission of Apollo 11,Armstrong and Aldrin Descended $\times$