What happens when two blocks, one nested inside of the other, both declare variables with the same identifier? (Assume that the outer block declares its variable before the opening left-brace of the inner block.)
A) A syntax error occurs.
B) The "outer" variable is hidden while the "inner" variable is in scope.
C) The "outer" variable is irretrievably lost when the "inner" variable is declared.
D) The "inner" declaration is ignored and the "outer" variable has scope even inside the inner block.

Question

Quizplus · Accepted Answer

When two blocks declare variables with the same identifier, the inner variable will "shadow" (i.e. hide) the outer variable while it is in scope. This means that any references to the variable within the inner block will refer to the inner variable, not the outer one. However, outside of the inner block, the outer variable will still be available.

What Happens When Two Blocks, One Nested Inside of the Other