The $\alpha$ form of polonium (Po)has a density of 9.196 g/cm³ and crystallizes in a simple cubic structure.What is the atomic radius of polonium?

Question

Quizplus · Accepted Answer

In a simple cubic structure, the edge length (a) is equal to twice the atomic radius (r). The density (ρ) is given by ρ = (Z * M) / (a^3 * N_A), where Z is the number of atoms per unit cell (1 for simple cubic), M is the molar mass, and N_A is Avogadro's number. Solving for a using the given density and molar mass of polonium (209 g/mol), we find a = 336 pm. The atomic radius is then a/2 = 168 pm.

The α\alphaα Form of Polonium (Po)has a Density of 9

The $\alpha$ Form of Polonium (Po)has a Density of 9