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Phosphoric Acid Is a Triprotic Acid in Water,ionizing in the Following

Question 95

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Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H3PO4 + H2O \leftrightarrows H2PO4- + H3O+  Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H<sub>3</sub>PO<sub>4</sub> + H<sub>2</sub>O  \leftrightarrows H<sub>2</sub>PO<sub>4</sub><sup>-</sup> + H<sub>3</sub>O<sup>+</sup>   = 7.11 *10<sup>-</sup><sup>3</sup> H<sub>2</sub>PO<sub>4</sub><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows HPO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 6.32 *10<sup>-</sup><sup>8</sup> HPO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows  PO<sub>4</sub><sup>3</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 4.5 *10<sup>-</sup><sup>13</sup> What is the pH of a 0.20 M Na<sub>3</sub>PO<sub>4</sub> solution? A) 1.66 B) 5.82 C) 10.50 D) 12.75 E) 12.82 = 7.11 *10-3
H2PO4- + H2O \leftrightarrows HPO42- + H3O+
 Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H<sub>3</sub>PO<sub>4</sub> + H<sub>2</sub>O  \leftrightarrows H<sub>2</sub>PO<sub>4</sub><sup>-</sup> + H<sub>3</sub>O<sup>+</sup>   = 7.11 *10<sup>-</sup><sup>3</sup> H<sub>2</sub>PO<sub>4</sub><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows HPO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 6.32 *10<sup>-</sup><sup>8</sup> HPO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows  PO<sub>4</sub><sup>3</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 4.5 *10<sup>-</sup><sup>13</sup> What is the pH of a 0.20 M Na<sub>3</sub>PO<sub>4</sub> solution? A) 1.66 B) 5.82 C) 10.50 D) 12.75 E) 12.82 = 6.32 *10-8
HPO42- + H2O \leftrightarrows PO43- + H3O+
 Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H<sub>3</sub>PO<sub>4</sub> + H<sub>2</sub>O  \leftrightarrows H<sub>2</sub>PO<sub>4</sub><sup>-</sup> + H<sub>3</sub>O<sup>+</sup>   = 7.11 *10<sup>-</sup><sup>3</sup> H<sub>2</sub>PO<sub>4</sub><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows HPO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 6.32 *10<sup>-</sup><sup>8</sup> HPO<sub>4</sub><sup>2</sup><sup>-</sup> + H<sub>2</sub>O  \leftrightarrows  PO<sub>4</sub><sup>3</sup><sup>-</sup> + H<sub>3</sub>O<sup>+ </sup> <sup> </sup>   = 4.5 *10<sup>-</sup><sup>13</sup> What is the pH of a 0.20 M Na<sub>3</sub>PO<sub>4</sub> solution? A) 1.66 B) 5.82 C) 10.50 D) 12.75 E) 12.82 = 4.5 *10-13
What is the pH of a 0.20 M Na3PO4 solution?


A) 1.66
B) 5.82
C) 10.50
D) 12.75
E) 12.82

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