Calculate the molality of a solution containing 0.355 mol sucrose (C₁₂H₂₂O₁₁)and 245 g of water.

Question

Quizplus · Accepted Answer

Molality (m) is defined as the number of moles of solute per kilogram of solvent. 
Firstly, we need to convert the mass of water from grams to kilograms: 
245 g of water = 0.245 kg of water 
Next, we can use the formula for molality: 
molality = moles of solute / kilograms of solvent 
molality = 0.355 mol / 0.245 kg 
molality ≈ 1.45 m (rounded to two significant figures) 
Therefore, the correct answer is choice B.

Calculate the Molality of a Solution Containing 0 ×\times× 10-2 M B)1

Calculate the Molality of a Solution Containing 0 $\times$ 10^-² M
B)1